945. Minimum Increment to Make Array Unique LeetCode Solution

In this guide, you will get 945. Minimum Increment to Make Array Unique LeetCode Solution with the best time and space complexity. The solution to Minimum Increment to Make Array Unique problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

  1. Problem Statement
  2. Complexity Analysis
  3. Minimum Increment to Make Array Unique solution in C++
  4. Minimum Increment to Make Array Unique solution in Java
  5. Minimum Increment to Make Array Unique solution in Python
  6. Additional Resources
945. Minimum Increment to Make Array Unique LeetCode Solution image

Problem Statement of Minimum Increment to Make Array Unique

You are given an integer array nums. In one move, you can pick an index i where 0 <= i < nums.length and increment nums[i] by 1.
Return the minimum number of moves to make every value in nums unique.
The test cases are generated so that the answer fits in a 32-bit integer.

Example 1:

Input: nums = [1,2,2]
Output: 1
Explanation: After 1 move, the array could be [1, 2, 3].

Example 2:

Input: nums = [3,2,1,2,1,7]
Output: 6
Explanation: After 6 moves, the array could be [3, 4, 1, 2, 5, 7].
It can be shown that it is impossible for the array to have all unique values with 5 or less moves.

Constraints:

1 <= nums.length <= 105
0 <= nums[i] <= 105

Complexity Analysis

  • Time Complexity: O(\texttt{sort})
  • Space Complexity: O(\texttt{sort})

945. Minimum Increment to Make Array Unique LeetCode Solution in C++

class Solution {
 public:
  int minIncrementForUnique(vector<int>& nums) {
    int ans = 0;
    int minAvailable = 0;

    ranges::sort(nums);

    for (const int num : nums) {
      ans += max(minAvailable - num, 0);
      minAvailable = max(minAvailable, num) + 1;
    }

    return ans;
  }
};
/* code provided by PROGIEZ */

945. Minimum Increment to Make Array Unique LeetCode Solution in Java

class Solution {
  public int minIncrementForUnique(int[] nums) {
    int ans = 0;
    int minAvailable = 0;

    Arrays.sort(nums);

    for (final int num : nums) {
      ans += Math.max(minAvailable - num, 0);
      minAvailable = Math.max(minAvailable, num) + 1;
    }

    return ans;
  }
}
// code provided by PROGIEZ

945. Minimum Increment to Make Array Unique LeetCode Solution in Python

class Solution:
  def minIncrementForUnique(self, nums: list[int]) -> int:
    ans = 0
    minAvailable = 0

    for num in sorted(nums):
      ans += max(minAvailable - num, 0)
      minAvailable = max(minAvailable, num) + 1

    return ans
# code by PROGIEZ

Additional Resources

See also  1206. Design Skiplist LeetCode Solution

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