73. Set Matrix Zeroes LeetCode Solution

In this guide, you will get 73. Set Matrix Zeroes LeetCode Solution with the best time and space complexity. The solution to Set Matrix Zeroes problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Problem Statement
Complexity Analysis
Set Matrix Zeroes solution in C++
Set Matrix Zeroes solution in Java
Set Matrix Zeroes solution in Python
Additional Resources

73. Set Matrix Zeroes LeetCode Solution image

Problem Statement of Set Matrix Zeroes

Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0’s.
You must do it in place.

Example 1:

Input: matrix = [[1,1,1],[1,0,1],[1,1,1]]
Output: [[1,0,1],[0,0,0],[1,0,1]]

Example 2:

Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]

Constraints:

m == matrix.length
n == matrix[0].length
1 <= m, n <= 200
-231 <= matrix[i][j] <= 231 – 1

Follow up:

A straightforward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?

Complexity Analysis

Time Complexity: O(mn)
Space Complexity: O(1)

73. Set Matrix Zeroes LeetCode Solution in C++

class Solution {
 public:
  void setZeroes(vector<vector<int>>& matrix) {
    const int m = matrix.size();
    const int n = matrix[0].size();
    bool shouldFillFirstRow = false;
    bool shouldFillFirstCol = false;

    for (int j = 0; j < n; ++j)
      if (matrix[0][j] == 0) {
        shouldFillFirstRow = true;
        break;
      }

    for (int i = 0; i < m; ++i)
      if (matrix[i][0] == 0) {
        shouldFillFirstCol = true;
        break;
      }

    // Store the information in the first row and the first column.
    for (int i = 1; i < m; ++i)
      for (int j = 1; j < n; ++j)
        if (matrix[i][j] == 0) {
          matrix[i][0] = 0;
          matrix[0][j] = 0;
        }

    // Fill 0s for the matrix except the first row and the first column.
    for (int i = 1; i < m; ++i)
      for (int j = 1; j < n; ++j)
        if (matrix[i][0] == 0 || matrix[0][j] == 0)
          matrix[i][j] = 0;

    // Fill 0s for the first row if needed.
    if (shouldFillFirstRow)
      for (int j = 0; j < n; ++j)
        matrix[0][j] = 0;

    // Fill 0s for the first column if needed.
    if (shouldFillFirstCol)
      for (int i = 0; i < m; ++i)
        matrix[i][0] = 0;
  }
};
/* code provided by PROGIEZ */

73. Set Matrix Zeroes LeetCode Solution in Java

class Solution {
  public void setZeroes(int[][] matrix) {
    final int m = matrix.length;
    final int n = matrix[0].length;
    boolean shouldFillFirstRow = false;
    boolean shouldFillFirstCol = false;

    for (int j = 0; j < n; ++j)
      if (matrix[0][j] == 0) {
        shouldFillFirstRow = true;
        break;
      }

    for (int i = 0; i < m; ++i)
      if (matrix[i][0] == 0) {
        shouldFillFirstCol = true;
        break;
      }

    // Store the information in the first row and the first column.
    for (int i = 1; i < m; ++i)
      for (int j = 1; j < n; ++j)
        if (matrix[i][j] == 0) {
          matrix[i][0] = 0;
          matrix[0][j] = 0;
        }

    // Fill 0s for the matrix except the first row and the first column.
    for (int i = 1; i < m; ++i)
      for (int j = 1; j < n; ++j)
        if (matrix[i][0] == 0 || matrix[0][j] == 0)
          matrix[i][j] = 0;

    // Fill 0s for the first row if needed.
    if (shouldFillFirstRow)
      for (int j = 0; j < n; ++j)
        matrix[0][j] = 0;

    // Fill 0s for the first column if needed.
    if (shouldFillFirstCol)
      for (int i = 0; i < m; ++i)
        matrix[i][0] = 0;
  }
}
// code provided by PROGIEZ

73. Set Matrix Zeroes LeetCode Solution in Python

class Solution:
  def setZeroes(self, matrix: list[list[int]]) -> None:
    m = len(matrix)
    n = len(matrix[0])
    shouldFillFirstRow = 0 in matrix[0]
    shouldFillFirstCol = 0 in list(zip(*matrix))[0]

    # Store the information in the first row and the first column.
    for i in range(1, m):
      for j in range(1, n):
        if matrix[i][j] == 0:
          matrix[i][0] = 0
          matrix[0][j] = 0

    # Fill 0s for the matrix except the first row and the first column.
    for i in range(1, m):
      for j in range(1, n):
        if matrix[i][0] == 0 or matrix[0][j] == 0:
          matrix[i][j] = 0

    # Fill 0s for the first row if needed.
    if shouldFillFirstRow:
      matrix[0] = [0] * n

    # Fill 0s for the first column if needed.
    if shouldFillFirstCol:
      for row in matrix:
        row[0] = 0
 # code by PROGIEZ