2721. Execute Asynchronous Functions in Parallel LeetCode Solution

In this guide, you will get 2721. Execute Asynchronous Functions in Parallel LeetCode Solution with the best time and space complexity. The solution to Execute Asynchronous Functions in Parallel problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

  1. Problem Statement
  2. Complexity Analysis
  3. Execute Asynchronous Functions in Parallel solution in C++
  4. Execute Asynchronous Functions in Parallel solution in Java
  5. Execute Asynchronous Functions in Parallel solution in Python
  6. Additional Resources
2721. Execute Asynchronous Functions in Parallel LeetCode Solution image

Problem Statement of Execute Asynchronous Functions in Parallel

Given an array of asynchronous functions functions, return a new promise promise. Each function in the array accepts no arguments and returns a promise. All the promises should be executed in parallel.
promise resolves:

When all the promises returned from functions were resolved successfully in parallel. The resolved value of promise should be an array of all the resolved values of promises in the same order as they were in the functions. The promise should resolve when all the asynchronous functions in the array have completed execution in parallel.

promise rejects:

When any of the promises returned from functions were rejected. promise should also reject with the reason of the first rejection.

Please solve it without using the built-in Promise.all function.

Example 1:

Input: functions = [
() => new Promise(resolve => setTimeout(() => resolve(5), 200))
]
Output: {“t”: 200, “resolved”: [5]}
Explanation:
promiseAll(functions).then(console.log); // [5]

See also  2386. Find the K-Sum of an Array LeetCode Solution

The single function was resolved at 200ms with a value of 5.

Example 2:

Input: functions = [
() => new Promise(resolve => setTimeout(() => resolve(1), 200)),
() => new Promise((resolve, reject) => setTimeout(() => reject(“Error”), 100))
]
Output: {“t”: 100, “rejected”: “Error”}
Explanation: Since one of the promises rejected, the returned promise also rejected with the same error at the same time.

Example 3:

Input: functions = [
() => new Promise(resolve => setTimeout(() => resolve(4), 50)),
() => new Promise(resolve => setTimeout(() => resolve(10), 150)),
() => new Promise(resolve => setTimeout(() => resolve(16), 100))
]
Output: {“t”: 150, “resolved”: [4, 10, 16]}
Explanation: All the promises resolved with a value. The returned promise resolved when the last promise resolved.

Constraints:

functions is an array of functions that returns promises
1 <= functions.length <= 10

Complexity Analysis

  • Time Complexity: Google AdSense
  • Space Complexity: Google Analytics

2721. Execute Asynchronous Functions in Parallel LeetCode Solution in C++

type Fn<T> = () => Promise<T>;

function promiseAll<T>(functions: Fn<T>[]): Promise<T[]> {
  return new Promise((resolve, reject) => {
    const ans: T[] = [];
    let resolveCount = 0;
    functions.forEach((fn, index) => {
      fn()
        .then((val) => {
          ans[index] = val;
          if (++resolveCount === functions.length) {
            resolve(ans);
          }
        })
        .catch((error) => {
          reject(error);
        });
    });
  });
}
/* code provided by PROGIEZ */

2721. Execute Asynchronous Functions in Parallel LeetCode Solution in Java

N/A
// code provided by PROGIEZ

2721. Execute Asynchronous Functions in Parallel LeetCode Solution in Python

N/A
# code by PROGIEZ

Additional Resources

Happy Coding! Keep following PROGIEZ for more updates and solutions.