Chef and Subarray : CHEFZOT

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Read problems statements in Mandarin Chinese and Russian.

Chef loves research! Now he is looking for subarray of maximal length with non-zero product.

Chef has an array A with N elements: A₁, A₂, …, A_N.

Subarray A_ij of array A is elements from index i to index j: A_i, A_i+1, …, A_j.

Product of subarray A_ij is product of all its elements (from i_th to j_th).

Input

• First line contains sinlge integer N denoting the number of elements.
• Second line contains N space-separated integers A₁, A₂, …, A_N denoting the elements of array.

Output

• In a single line print single integer – the maximal length of subarray with non-zero product.

Constraints

• 1 ≤ N ≤ 100000
• 0 ≤ A_i ≤ 10000

Sample Input 1 

6
1 0 2 3 0 4

Sample Output 1 

2

Explanation

For the first sample subarray is: {2, 3}.

Sample Input 2 

1
0

Sample Output 2 

0

Explanation

For the second sample there are no subbarays with non-zero product.

Sample Input 3 

3
1 0 1

Sample Output 3 

1

Explanation

For the third sample subbarays is {1}, (the first element, or the third one).

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Chef and Subarray Codechef Solution in C

int main(void)
{
    int N,i,j,c,max=0;
    int arr[100000];
    scanf("%d",&N);
    for(i=0;i < N;i++)
    {
        scanf("%d",&arr[i]);
    }
    for(i=0;i < N;i++)
    {
        c=0;
        for(j=i;j < N&&arr[j]!=0;j++,c++)
        {}
        max=((max < c)?c:max);
    }
    printf("%d",max);
	return 0;
}

Chef and Subarray Codechef Solution in C++ 14

int main() {
        int n;
        cin>>n;int c=0;int m=0;
        int a[n];
        for(int i=0;i < n;i++)
        {
            cin>>a[i];
            if(a[i]!=0)
            {
                c=c+1;//cout << c << endl;
            }
            else{
                if(c>m)
                {
                    m=c;//cout << "max:" << m << endl;
                }
                c=0;
            }
        }
        if(c>m)
        {
            m=c;
        }
        cout << m << endl;
	return 0;
}

Chef and Subarray Codechef Solution in Python 3

# cook your dish here
n = int(input())
arr = list(map(int,input().split()))
count=0
j,ans=0,0
while(j < n):
    if arr[j]!=0:
        count+=1

    else:
        ans=max(ans,count)
        count=0
    j+=1
ans=max(ans,count)
print(ans)

Chef and Subarray Codechef Solution in Java

currently not available

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