1519. Number of Nodes in the Sub-Tree With the Same Label LeetCode Solution
In this guide, you will get 1519. Number of Nodes in the Sub-Tree With the Same Label LeetCode Solution with the best time and space complexity. The solution to Number of Nodes in the Sub-Tree With the Same Label problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.
Table of Contents
- Problem Statement
- Complexity Analysis
- Number of Nodes in the Sub-Tree With the Same Label solution in C++
- Number of Nodes in the Sub-Tree With the Same Label solution in Java
- Number of Nodes in the Sub-Tree With the Same Label solution in Python
- Additional Resources

Problem Statement of Number of Nodes in the Sub-Tree With the Same Label
You are given a tree (i.e. a connected, undirected graph that has no cycles) consisting of n nodes numbered from 0 to n – 1 and exactly n – 1 edges. The root of the tree is the node 0, and each node of the tree has a label which is a lower-case character given in the string labels (i.e. The node with the number i has the label labels[i]).
The edges array is given on the form edges[i] = [ai, bi], which means there is an edge between nodes ai and bi in the tree.
Return an array of size n where ans[i] is the number of nodes in the subtree of the ith node which have the same label as node i.
A subtree of a tree T is the tree consisting of a node in T and all of its descendant nodes.
Example 1:
Input: n = 7, edges = [[0,1],[0,2],[1,4],[1,5],[2,3],[2,6]], labels = “abaedcd”
Output: [2,1,1,1,1,1,1]
Explanation: Node 0 has label ‘a’ and its sub-tree has node 2 with label ‘a’ as well, thus the answer is 2. Notice that any node is part of its sub-tree.
Node 1 has a label ‘b’. The sub-tree of node 1 contains nodes 1,4 and 5, as nodes 4 and 5 have different labels than node 1, the answer is just 1 (the node itself).
Example 2:
Input: n = 4, edges = [[0,1],[1,2],[0,3]], labels = “bbbb”
Output: [4,2,1,1]
Explanation: The sub-tree of node 2 contains only node 2, so the answer is 1.
The sub-tree of node 3 contains only node 3, so the answer is 1.
The sub-tree of node 1 contains nodes 1 and 2, both have label ‘b’, thus the answer is 2.
The sub-tree of node 0 contains nodes 0, 1, 2 and 3, all with label ‘b’, thus the answer is 4.
Example 3:
Input: n = 5, edges = [[0,1],[0,2],[1,3],[0,4]], labels = “aabab”
Output: [3,2,1,1,1]
Constraints:
1 <= n <= 105
edges.length == n – 1
edges[i].length == 2
0 <= ai, bi < n
ai != bi
labels.length == n
labels is consisting of only of lowercase English letters.
Complexity Analysis
- Time Complexity: O(n)
- Space Complexity: O(n)
1519. Number of Nodes in the Sub-Tree With the Same Label LeetCode Solution in C++
class Solution {
public:
vector<int> countSubTrees(int n, vector<vector<int>>& edges, string labels) {
vector<int> ans(n);
vector<vector<int>> tree(n);
for (const vector<int>& edge : edges) {
const int u = edge[0];
const int v = edge[1];
tree[u].push_back(v);
tree[v].push_back(u);
}
dfs(tree, 0, -1, labels, ans);
return ans;
}
private:
vector<int> dfs(const vector<vector<int>>& tree, int u, int prev,
const string& labels, vector<int>& ans) {
// count[i] := the number of letters down from ('a' + i)
vector<int> count(26);
for (const int v : tree[u]) {
if (v == prev)
continue;
vector<int> childCount = dfs(tree, v, u, labels, ans);
for (int i = 0; i < 26; ++i)
count[i] += childCount[i];
}
ans[u] = ++count[labels[u] - 'a']; // the u itself
return count;
}
};
/* code provided by PROGIEZ */
1519. Number of Nodes in the Sub-Tree With the Same Label LeetCode Solution in Java
class Solution {
public int[] countSubTrees(int n, int[][] edges, String labels) {
int[] ans = new int[n];
List<Integer>[] graph = new List[n];
for (int i = 0; i < n; ++i)
graph[i] = new ArrayList<>();
for (int[] edge : edges) {
final int u = edge[0];
final int v = edge[1];
graph[u].add(v);
graph[v].add(u);
}
dfs(graph, 0, -1, labels, ans);
return ans;
}
private int[] dfs(List<Integer>[] graph, int u, int prev, final String labels, int[] ans) {
// count[i] := the number of letters down from ('a' + i)
int[] count = new int[26];
for (final int v : graph[u]) {
if (v == prev)
continue;
int[] childCount = dfs(graph, v, u, labels, ans);
for (int i = 0; i < 26; ++i)
count[i] += childCount[i];
}
ans[u] = ++count[labels.charAt(u) - 'a']; // the u itself
return count;
}
}
// code provided by PROGIEZ
1519. Number of Nodes in the Sub-Tree With the Same Label LeetCode Solution in Python
N/A
# code by PROGIEZ
Additional Resources
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- Explore all problems on LeetCode website here
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