In this guide, you will get 3295. Report Spam Message LeetCode Solution with the best time and space complexity. The solution to Report Spam Message problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.
You are given an array of strings message and an array of strings bannedWords.
An array of words is considered spam if there are at least two words in it that exactly match any word in bannedWords.
Return true if the array message is spam, and false otherwise.
Example 1:
Input: message = [“hello”,”world”,”leetcode”], bannedWords = [“world”,”hello”]
Output: true
Explanation:
The words “hello” and “world” from the message array both appear in the bannedWords array.
Example 2:
Input: message = [“hello”,”programming”,”fun”], bannedWords = [“world”,”programming”,”leetcode”]
Output: false
Explanation:
Only one word from the message array (“programming”) appears in the bannedWords array.
Constraints:
1 <= message.length, bannedWords.length <= 105
1 <= message[i].length, bannedWords[i].length <= 15
message[i] and bannedWords[i] consist only of lowercase English letters.
Complexity Analysis
Time Complexity: O(|\texttt{message}| + |\texttt{bannedWords}|)
Space Complexity: O(|\texttt{bannedWords}|)
3295. Report Spam Message LeetCode Solution in C++
class Solution {
public:
bool reportSpam(vector<string>& message, vector<string>& bannedWords) {
const unordered_set<string> bannedWordsSet{bannedWords.begin(),
bannedWords.end()};
int count = 0;
for (const string& word : message)
if (bannedWordsSet.contains(word) && ++count > 1)
return true;
return false;
}
}; /* code provided by PROGIEZ */
3295. Report Spam Message LeetCode Solution in Java
class Solution {
public boolean reportSpam(String[] message, String[] bannedWords) {
Set<String> bannedWordsSet = new HashSet<>(Arrays.asList(bannedWords));
int count = 0;
for (final String word : message)
if (bannedWordsSet.contains(word) && ++count > 1)
return true;
return false;
}
} // code provided by PROGIEZ
3295. Report Spam Message LeetCode Solution in Python
class Solution:
def reportSpam(self, message: list[str], bannedWords: list[str]) -> bool:
bannedWordsSet = set(bannedWords)
return sum(word in bannedWordsSet for word in message) > 1 # code by PROGIEZ
