2943. Maximize Area of Square Hole in Grid LeetCode Solution

In this guide, you will get 2943. Maximize Area of Square Hole in Grid LeetCode Solution with the best time and space complexity. The solution to Maximize Area of Square Hole in Grid problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

1. Problem Statement
2. Complexity Analysis
3. Maximize Area of Square Hole in Grid solution in C++
4. Maximize Area of Square Hole in Grid solution in Java
5. Maximize Area of Square Hole in Grid solution in Python
6. Additional Resources

Problem Statement of Maximize Area of Square Hole in Grid

You are given the two integers, n and m and two integer arrays, hBars and vBars. The grid has n + 2 horizontal and m + 2 vertical bars, creating 1 x 1 unit cells. The bars are indexed starting from 1.
You can remove some of the bars in hBars from horizontal bars and some of the bars in vBars from vertical bars. Note that other bars are fixed and cannot be removed.
Return an integer denoting the maximum area of a square-shaped hole in the grid, after removing some bars (possibly none).

Example 1:

Input: n = 2, m = 1, hBars = [2,3], vBars = [2]
Output: 4
Explanation:
The left image shows the initial grid formed by the bars. The horizontal bars are [1,2,3,4], and the vertical bars are [1,2,3].
One way to get the maximum square-shaped hole is by removing horizontal bar 2 and vertical bar 2.

Example 2:

Input: n = 1, m = 1, hBars = [2], vBars = [2]
Output: 4
Explanation:
To get the maximum square-shaped hole, we remove horizontal bar 2 and vertical bar 2.

Example 3:

Input: n = 2, m = 3, hBars = [2,3], vBars = [2,4]
Output: 4
Explanation:
One way to get the maximum square-shaped hole is by removing horizontal bar 3, and vertical bar 4.

Constraints:

1 <= n <= 109
1 <= m <= 109
1 <= hBars.length <= 100
2 <= hBars[i] <= n + 1
1 <= vBars.length <= 100
2 <= vBars[i] <= m + 1
All values in hBars are distinct.
All values in vBars are distinct.

Complexity Analysis

• Time Complexity: O(\texttt{sort}(\texttt{hBars}) + \texttt{sort}(\texttt{vBars}))
• Space Complexity: O(\texttt{sort}(\texttt{hBars}) + \texttt{sort}(\texttt{vBars}))

2943. Maximize Area of Square Hole in Grid LeetCode Solution in C++

class Solution {
 public:
  int maximizeSquareHoleArea(int n, int m, vector<int>& hBars,
                             vector<int>& vBars) {
    const int gap = min(maxContinousGap(hBars), maxContinousGap(vBars));
    return gap * gap;
  }

 private:
  int maxContinousGap(vector<int>& bars) {
    int res = 2;
    int runningGap = 2;
    ranges::sort(bars);
    for (int i = 1; i < bars.size(); ++i) {
      runningGap = bars[i] == bars[i - 1] + 1 ? runningGap + 1 : 2;
      res = max(res, runningGap);
    }
    return res;
  }
};
/* code provided by PROGIEZ */

2943. Maximize Area of Square Hole in Grid LeetCode Solution in Java

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// code provided by PROGIEZ

2943. Maximize Area of Square Hole in Grid LeetCode Solution in Python

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Additional Resources

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