1827. Minimum Operations to Make the Array Increasing LeetCode Solution

In this guide, you will get 1827. Minimum Operations to Make the Array Increasing LeetCode Solution with the best time and space complexity. The solution to Minimum Operations to Make the Array Increasing problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

1. Problem Statement
2. Complexity Analysis
3. Minimum Operations to Make the Array Increasing solution in C++
4. Minimum Operations to Make the Array Increasing solution in Java
5. Minimum Operations to Make the Array Increasing solution in Python
6. Additional Resources

Problem Statement of Minimum Operations to Make the Array Increasing

You are given an integer array nums (0-indexed). In one operation, you can choose an element of the array and increment it by 1.

For example, if nums = [1,2,3], you can choose to increment nums[1] to make nums = [1,3,3].

Return the minimum number of operations needed to make nums strictly increasing.
An array nums is strictly increasing if nums[i] < nums[i+1] for all 0 <= i < nums.length – 1. An array of length 1 is trivially strictly increasing.

Example 1:

Input: nums = [1,1,1]
Output: 3
Explanation: You can do the following operations:
1) Increment nums[2], so nums becomes [1,1,2].
2) Increment nums[1], so nums becomes [1,2,2].
3) Increment nums[2], so nums becomes [1,2,3].

Example 2:

Input: nums = [1,5,2,4,1]
Output: 14

Example 3:

Input: nums = [8]
Output: 0

Constraints:

1 <= nums.length <= 5000
1 <= nums[i] <= 104

Complexity Analysis

• Time Complexity: O(n)
• Space Complexity: O(1)

1827. Minimum Operations to Make the Array Increasing LeetCode Solution in C++

class Solution {
 public:
  int minOperations(vector<int>& nums) {
    int ans = 0;
    int last = 0;

    for (const int num : nums) {
      ans += max(0, last - num + 1);
      last = max(num, last + 1);
    }

    return ans;
  }
};
/* code provided by PROGIEZ */

1827. Minimum Operations to Make the Array Increasing LeetCode Solution in Java

class Solution {
  public int minOperations(int[] nums) {
    int ans = 0;
    int last = 0;

    for (final int num : nums) {
      ans += Math.max(0, last - num + 1);
      last = Math.max(num, last + 1);
    }

    return ans;
  }
}
// code provided by PROGIEZ

1827. Minimum Operations to Make the Array Increasing LeetCode Solution in Python

class Solution:
  def minOperations(self, nums: list[int]) -> int:
    ans = 0
    last = 0

    for num in nums:
      ans += max(0, last - num + 1)
      last = max(num, last + 1)

    return ans
 # code by PROGIEZ

Additional Resources

• Explore all LeetCode problem solutions at Progiez here
• Explore all problems on LeetCode website here

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