1688. Count of Matches in Tournament LeetCode Solution

In this guide, you will get 1688. Count of Matches in Tournament LeetCode Solution with the best time and space complexity. The solution to Count of Matches in Tournament problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

  1. Problem Statement
  2. Complexity Analysis
  3. Count of Matches in Tournament solution in C++
  4. Count of Matches in Tournament solution in Java
  5. Count of Matches in Tournament solution in Python
  6. Additional Resources
1688. Count of Matches in Tournament LeetCode Solution image

Problem Statement of Count of Matches in Tournament

You are given an integer n, the number of teams in a tournament that has strange rules:

If the current number of teams is even, each team gets paired with another team. A total of n / 2 matches are played, and n / 2 teams advance to the next round.
If the current number of teams is odd, one team randomly advances in the tournament, and the rest gets paired. A total of (n – 1) / 2 matches are played, and (n – 1) / 2 + 1 teams advance to the next round.

Return the number of matches played in the tournament until a winner is decided.

Example 1:

Input: n = 7
Output: 6
Explanation: Details of the tournament:
– 1st Round: Teams = 7, Matches = 3, and 4 teams advance.
– 2nd Round: Teams = 4, Matches = 2, and 2 teams advance.
– 3rd Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 3 + 2 + 1 = 6.

Example 2:

Input: n = 14
Output: 13
Explanation: Details of the tournament:
– 1st Round: Teams = 14, Matches = 7, and 7 teams advance.
– 2nd Round: Teams = 7, Matches = 3, and 4 teams advance.
– 3rd Round: Teams = 4, Matches = 2, and 2 teams advance.
– 4th Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 7 + 3 + 2 + 1 = 13.

Constraints:

1 <= n <= 200

Complexity Analysis

  • Time Complexity:
  • Space Complexity:

1688. Count of Matches in Tournament LeetCode Solution in C++

class Solution {
 public:
  int numberOfMatches(int n) {
    return n - 1;
  }
};
/* code provided by PROGIEZ */

1688. Count of Matches in Tournament LeetCode Solution in Java

class Solution {
  public int numberOfMatches(int n) {
    return n - 1;
  }
}
// code provided by PROGIEZ

1688. Count of Matches in Tournament LeetCode Solution in Python

class Solution:
  def numberOfMatches(self, n: int) -> int:
    return n - 1
# code by PROGIEZ

Additional Resources

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