1526. Minimum Number of Increments on Subarrays to Form a Target Array LeetCode Solution
In this guide, you will get 1526. Minimum Number of Increments on Subarrays to Form a Target Array LeetCode Solution with the best time and space complexity. The solution to Minimum Number of Increments on Subarrays to Form a Target Array problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.
Problem Statement of Minimum Number of Increments on Subarrays to Form a Target Array
You are given an integer array target. You have an integer array initial of the same size as target with all elements initially zeros.
In one operation you can choose any subarray from initial and increment each value by one.
Return the minimum number of operations to form a target array from initial.
The test cases are generated so that the answer fits in a 32-bit integer.
Example 1:
Input: target = [1,2,3,2,1]
Output: 3
Explanation: We need at least 3 operations to form the target array from the initial array.
[0,0,0,0,0] increment 1 from index 0 to 4 (inclusive).
[1,1,1,1,1] increment 1 from index 1 to 3 (inclusive).
[1,2,2,2,1] increment 1 at index 2.
[1,2,3,2,1] target array is formed.
1526. Minimum Number of Increments on Subarrays to Form a Target Array LeetCode Solution in C++
class Solution {
public:
int minNumberOperations(vector<int>& target) {
int ans = target.front();
for (int i = 1; i < target.size(); ++i)
if (target[i] > target[i - 1])
ans += target[i] - target[i - 1];
return ans;
}
}; /* code provided by PROGIEZ */
1526. Minimum Number of Increments on Subarrays to Form a Target Array LeetCode Solution in Java
class Solution {
public int minNumberOperations(int[] target) {
int ans = target[0];
for (int i = 1; i < target.length; ++i)
if (target[i] > target[i - 1])
ans += target[i] - target[i - 1];
return ans;
}
} // code provided by PROGIEZ
1526. Minimum Number of Increments on Subarrays to Form a Target Array LeetCode Solution in Python
class Solution:
def minNumberOperations(self, target: list[int]) -> int:
ans = target[0]
for a, b in zip(target, target[1:]):
if a < b:
ans += b - a
return ans # code by PROGIEZ
