1413. Minimum Value to Get Positive Step by Step Sum LeetCode Solution
In this guide, you will get 1413. Minimum Value to Get Positive Step by Step Sum LeetCode Solution with the best time and space complexity. The solution to Minimum Value to Get Positive Step by Step Sum problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.
Problem Statement of Minimum Value to Get Positive Step by Step Sum
Given an array of integers nums, you start with an initial positive value startValue.
In each iteration, you calculate the step by step sum of startValue plus elements in nums (from left to right).
Return the minimum positive value of startValue such that the step by step sum is never less than 1.
Example 1:
Input: nums = [-3,2,-3,4,2]
Output: 5
Explanation: If you choose startValue = 4, in the third iteration your step by step sum is less than 1.
step by step sum
startValue = 4 | startValue = 5 | nums
(4 -3 ) = 1 | (5 -3 ) = 2 | -3
(1 +2 ) = 3 | (2 +2 ) = 4 | 2
(3 -3 ) = 0 | (4 -3 ) = 1 | -3
(0 +4 ) = 4 | (1 +4 ) = 5 | 4
(4 +2 ) = 6 | (5 +2 ) = 7 | 2
Example 2:
Input: nums = [1,2]
Output: 1
Explanation: Minimum start value should be positive.
1413. Minimum Value to Get Positive Step by Step Sum LeetCode Solution in C++
class Solution {
public:
int minStartValue(vector<int>& nums) {
int sum = 0;
int minSum = 0;
for (const int num : nums)
minSum = min(minSum, sum += num);
return 1 - minSum;
}
}; /* code provided by PROGIEZ */
1413. Minimum Value to Get Positive Step by Step Sum LeetCode Solution in Java
class Solution {
public int minStartValue(int[] nums) {
int sum = 0;
int minSum = 0;
for (final int num : nums)
minSum = Math.min(minSum, sum += num);
return 1 - minSum;
}
} // code provided by PROGIEZ
1413. Minimum Value to Get Positive Step by Step Sum LeetCode Solution in Python
class Solution:
def minStartValue(self, nums: list[int]) -> int:
summ = 0
minSum = 0
for num in nums:
summ += num
minSum = min(minSum, summ)
return 1 - minSum # code by PROGIEZ
