1138. Alphabet Board Path LeetCode Solution

In this guide, you will get 1138. Alphabet Board Path LeetCode Solution with the best time and space complexity. The solution to Alphabet Board Path problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

1. Problem Statement
2. Complexity Analysis
3. Alphabet Board Path solution in C++
4. Alphabet Board Path solution in Java
5. Alphabet Board Path solution in Python
6. Additional Resources

Problem Statement of Alphabet Board Path

On an alphabet board, we start at position (0, 0), corresponding to character board[0][0].
Here, board = [“abcde”, “fghij”, “klmno”, “pqrst”, “uvwxy”, “z”], as shown in the diagram below.

We may make the following moves:

‘U’ moves our position up one row, if the position exists on the board;
‘D’ moves our position down one row, if the position exists on the board;
‘L’ moves our position left one column, if the position exists on the board;
‘R’ moves our position right one column, if the position exists on the board;
‘!’ adds the character board[r][c] at our current position (r, c) to the answer.

(Here, the only positions that exist on the board are positions with letters on them.)
Return a sequence of moves that makes our answer equal to target in the minimum number of moves. You may return any path that does so.

Example 1:
Input: target = “leet”
Output: “DDR!UURRR!!DDD!”
Example 2:
Input: target = “code”
Output: “RR!DDRR!UUL!R!”

Constraints:

1 <= target.length <= 100
target consists only of English lowercase letters.

Complexity Analysis

• Time Complexity:
• Space Complexity:

1138. Alphabet Board Path LeetCode Solution in C++

class Solution {
 public:
  string alphabetBoardPath(string target) {
    string ans;
    int x = 0;
    int y = 0;

    for (char c : target) {
      int newX = (c - 'a') % 5;
      int newY = (c - 'a') / 5;
      ans += string(max(0, y - newY), 'U') + string(max(0, newX - x), 'R') +
             string(max(0, x - newX), 'L') + string(max(0, newY - y), 'D') +
             '!';
      x = newX;
      y = newY;
    }

    return ans;
  }
};
/* code provided by PROGIEZ */

1138. Alphabet Board Path LeetCode Solution in Java

N/A
// code provided by PROGIEZ

1138. Alphabet Board Path LeetCode Solution in Python

N/A
 # code by PROGIEZ

Additional Resources

• Explore all LeetCode problem solutions at Progiez here
• Explore all problems on LeetCode website here

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