1072. Flip Columns For Maximum Number of Equal Rows LeetCode Solution

In this guide, you will get 1072. Flip Columns For Maximum Number of Equal Rows LeetCode Solution with the best time and space complexity. The solution to Flip Columns For Maximum Number of Equal Rows problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

1. Problem Statement
2. Complexity Analysis
3. Flip Columns For Maximum Number of Equal Rows solution in C++
4. Flip Columns For Maximum Number of Equal Rows solution in Java
5. Flip Columns For Maximum Number of Equal Rows solution in Python
6. Additional Resources

Problem Statement of Flip Columns For Maximum Number of Equal Rows

You are given an m x n binary matrix matrix.
You can choose any number of columns in the matrix and flip every cell in that column (i.e., Change the value of the cell from 0 to 1 or vice versa).
Return the maximum number of rows that have all values equal after some number of flips.

Example 1:

Input: matrix = [[0,1],[1,1]]
Output: 1
Explanation: After flipping no values, 1 row has all values equal.

Example 2:

Input: matrix = [[0,1],[1,0]]
Output: 2
Explanation: After flipping values in the first column, both rows have equal values.

Example 3:

Input: matrix = [[0,0,0],[0,0,1],[1,1,0]]
Output: 2
Explanation: After flipping values in the first two columns, the last two rows have equal values.

Constraints:

m == matrix.length
n == matrix[i].length
1 <= m, n <= 300
matrix[i][j] is either 0 or 1.

Complexity Analysis

• Time Complexity:
• Space Complexity:

1072. Flip Columns For Maximum Number of Equal Rows LeetCode Solution in C++

class Solution {
 public:
  int maxEqualRowsAfterFlips(vector<vector<int>>& matrix) {
    const int m = matrix.size();
    const int n = matrix[0].size();
    int ans = 0;
    vector<int> flip(n);
    unordered_set<int> seen;

    for (int i = 0; i < m; ++i) {
      if (seen.contains(i))
        continue;
      int count = 0;
      for (int j = 0; j < n; ++j)
        flip[j] = 1 ^ matrix[i][j];
      for (int k = 0; k < m; ++k)
        if (matrix[k] == matrix[i] || matrix[k] == flip) {
          seen.insert(k);
          ++count;
        }
      ans = max(ans, count);
    }

    return ans;
  }
};
/* code provided by PROGIEZ */

1072. Flip Columns For Maximum Number of Equal Rows LeetCode Solution in Java

class Solution {
  public int maxEqualRowsAfterFlips(int[][] matrix) {
    final int m = matrix.length;
    final int n = matrix[0].length;
    int ans = 0;
    int[] flip = new int[n];
    Set<Integer> seen = new HashSet<>();

    for (int i = 0; i < m; ++i) {
      if (seen.contains(i))
        continue;
      int count = 0;
      for (int j = 0; j < n; ++j)
        flip[j] = 1 ^ matrix[i][j];
      for (int k = 0; k < m; ++k)
        if (Arrays.equals(matrix[k], matrix[i]) || Arrays.equals(matrix[k], flip)) {
          seen.add(k);
          ++count;
        }
      ans = Math.max(ans, count);
    }

    return ans;
  }
}
// code provided by PROGIEZ

1072. Flip Columns For Maximum Number of Equal Rows LeetCode Solution in Python

class Solution:
  def maxEqualRowsAfterFlips(self, matrix: list[list[int]]) -> int:
    patterns = [tuple(a ^ row[0] for a in row) for row in matrix]
    return max(Counter(patterns).values())
 # code by PROGIEZ

Additional Resources

• Explore all LeetCode problem solutions at Progiez here
• Explore all problems on LeetCode website here

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