2997. Minimum Number of Operations to Make Array XOR Equal to K LeetCode Solution
In this guide, you will get 2997. Minimum Number of Operations to Make Array XOR Equal to K LeetCode Solution with the best time and space complexity. The solution to Minimum Number of Operations to Make Array XOR Equal to K problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.
Table of Contents
- Problem Statement
- Complexity Analysis
- Minimum Number of Operations to Make Array XOR Equal to K solution in C++
- Minimum Number of Operations to Make Array XOR Equal to K solution in Java
- Minimum Number of Operations to Make Array XOR Equal to K solution in Python
- Additional Resources

Problem Statement of Minimum Number of Operations to Make Array XOR Equal to K
You are given a 0-indexed integer array nums and a positive integer k.
You can apply the following operation on the array any number of times:
Choose any element of the array and flip a bit in its binary representation. Flipping a bit means changing a 0 to 1 or vice versa.
Return the minimum number of operations required to make the bitwise XOR of all elements of the final array equal to k.
Note that you can flip leading zero bits in the binary representation of elements. For example, for the number (101)2 you can flip the fourth bit and obtain (1101)2.
Example 1:
Input: nums = [2,1,3,4], k = 1
Output: 2
Explanation: We can do the following operations:
– Choose element 2 which is 3 == (011)2, we flip the first bit and we obtain (010)2 == 2. nums becomes [2,1,2,4].
– Choose element 0 which is 2 == (010)2, we flip the third bit and we obtain (110)2 = 6. nums becomes [6,1,2,4].
The XOR of elements of the final array is (6 XOR 1 XOR 2 XOR 4) == 1 == k.
It can be shown that we cannot make the XOR equal to k in less than 2 operations.
Example 2:
Input: nums = [2,0,2,0], k = 0
Output: 0
Explanation: The XOR of elements of the array is (2 XOR 0 XOR 2 XOR 0) == 0 == k. So no operation is needed.
Constraints:
1 <= nums.length <= 105
0 <= nums[i] <= 106
0 <= k <= 106
Complexity Analysis
- Time Complexity: O(n)
- Space Complexity: O(1)
2997. Minimum Number of Operations to Make Array XOR Equal to K LeetCode Solution in C++
class Solution {
public:
int minOperations(vector<int>& nums, unsigned k) {
const unsigned xors = accumulate(nums.begin(), nums.end(), 0, bit_xor<>());
return popcount(k ^ xors);
}
};
/* code provided by PROGIEZ */
2997. Minimum Number of Operations to Make Array XOR Equal to K LeetCode Solution in Java
class Solution {
public int minOperations(int[] nums, int k) {
final int xors = Arrays.stream(nums).reduce((a, b) -> a ^ b).getAsInt();
return Integer.bitCount(k ^ xors);
}
}
// code provided by PROGIEZ
2997. Minimum Number of Operations to Make Array XOR Equal to K LeetCode Solution in Python
class Solution:
def minOperations(self, nums: list[int], k: int) -> int:
return functools.reduce(operator.xor, nums, k).bit_count()
# code by PROGIEZ
Additional Resources
- Explore all LeetCode problem solutions at Progiez here
- Explore all problems on LeetCode website here
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