2620. Counter LeetCode Solution

In this guide, you will get 2620. Counter LeetCode Solution with the best time and space complexity. The solution to Counter problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

1. Problem Statement
2. Complexity Analysis
3. Counter solution in C++
4. Counter solution in Java
5. Counter solution in Python
6. Additional Resources

Problem Statement of Counter

Given an integer n, return a counter function. This counter function initially returns n and then returns 1 more than the previous value every subsequent time it is called (n, n + 1, n + 2, etc).

Example 1:

Input:
n = 10
[“call”,”call”,”call”]
Output: [10,11,12]
Explanation:
counter() = 10 // The first time counter() is called, it returns n.
counter() = 11 // Returns 1 more than the previous time.
counter() = 12 // Returns 1 more than the previous time.

Example 2:

Input:
n = -2
[“call”,”call”,”call”,”call”,”call”]
Output: [-2,-1,0,1,2]
Explanation: counter() initially returns -2. Then increases after each sebsequent call.

Constraints:

-1000 <= n <= 1000
0 <= calls.length <= 1000
calls[i] === "call"

Complexity Analysis

• Time Complexity: Google AdSense
• Space Complexity: Google Analytics

2620. Counter LeetCode Solution in C++

function createCounter(n: number): () => number {
  return function () {
    return n++;
  };
}
/* code provided by PROGIEZ */

2620. Counter LeetCode Solution in Java

N/A
// code provided by PROGIEZ

2620. Counter LeetCode Solution in Python

N/A
 # code by PROGIEZ

Additional Resources

• Explore all LeetCode problem solutions at Progiez here
• Explore all problems on LeetCode website here

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