1452. People Whose List of Favorite Companies Is Not a Subset of Another List LeetCode Solution

In this guide, you will get 1452. People Whose List of Favorite Companies Is Not a Subset of Another List LeetCode Solution with the best time and space complexity. The solution to People Whose List of Favorite Companies Is Not a Subset of Another List problem is provided in various programming languages like C++, Java, and Python. This will be helpful for you if you are preparing for placements, hackathons, interviews, or practice purposes. The solutions provided here are very easy to follow and include detailed explanations.

Table of Contents

  1. Problem Statement
  2. Complexity Analysis
  3. People Whose List of Favorite Companies Is Not a Subset of Another List solution in C++
  4. People Whose List of Favorite Companies Is Not a Subset of Another List solution in Java
  5. People Whose List of Favorite Companies Is Not a Subset of Another List solution in Python
  6. Additional Resources
1452. People Whose List of Favorite Companies Is Not a Subset of Another List LeetCode Solution image

Problem Statement of People Whose List of Favorite Companies Is Not a Subset of Another List

Given the array favoriteCompanies where favoriteCompanies[i] is the list of favorites companies for the ith person (indexed from 0).
Return the indices of people whose list of favorite companies is not a subset of any other list of favorites companies. You must return the indices in increasing order.

Example 1:

Input: favoriteCompanies = [[“leetcode”,”google”,”facebook”],[“google”,”microsoft”],[“google”,”facebook”],[“google”],[“amazon”]]
Output: [0,1,4]
Explanation:
Person with index=2 has favoriteCompanies[2]=[“google”,”facebook”] which is a subset of favoriteCompanies[0]=[“leetcode”,”google”,”facebook”] corresponding to the person with index 0.
Person with index=3 has favoriteCompanies[3]=[“google”] which is a subset of favoriteCompanies[0]=[“leetcode”,”google”,”facebook”] and favoriteCompanies[1]=[“google”,”microsoft”].
Other lists of favorite companies are not a subset of another list, therefore, the answer is [0,1,4].

See also  2034. Stock Price Fluctuation LeetCode Solution

Example 2:

Input: favoriteCompanies = [[“leetcode”,”google”,”facebook”],[“leetcode”,”amazon”],[“facebook”,”google”]]
Output: [0,1]
Explanation: In this case favoriteCompanies[2]=[“facebook”,”google”] is a subset of favoriteCompanies[0]=[“leetcode”,”google”,”facebook”], therefore, the answer is [0,1].

Example 3:

Input: favoriteCompanies = [[“leetcode”],[“google”],[“facebook”],[“amazon”]]
Output: [0,1,2,3]

Constraints:

1 <= favoriteCompanies.length <= 100
1 <= favoriteCompanies[i].length <= 500
1 <= favoriteCompanies[i][j].length <= 20
All strings in favoriteCompanies[i] are distinct.
All lists of favorite companies are distinct, that is, If we sort alphabetically each list then favoriteCompanies[i] != favoriteCompanies[j].
All strings consist of lowercase English letters only.

Complexity Analysis

  • Time Complexity:
  • Space Complexity:

1452. People Whose List of Favorite Companies Is Not a Subset of Another List LeetCode Solution in C++

class Solution:
  def peopleIndexes(self, favoriteCompanies: list[list[str]]) -> list[int]:
    ans = []
    n = len(favoriteCompanies)
    companies = [set(comp) for comp in favoriteCompanies]

    for i in range(n):
      find = False
      for j in range(n):
        if i == j:
          continue
        if companies[i].issubset(companies[j]):
          find = True
          break
      if not find:
        ans.append(i)

    return ans
/* code provided by PROGIEZ */

1452. People Whose List of Favorite Companies Is Not a Subset of Another List LeetCode Solution in Java

N/A
// code provided by PROGIEZ

1452. People Whose List of Favorite Companies Is Not a Subset of Another List LeetCode Solution in Python

N/A
 # code by PROGIEZ

Additional Resources

Happy Coding! Keep following PROGIEZ for more updates and solutions.

Similar: