Introduction to Programming in C Week 8

Session: JAN-APR 2024

Course Name: Introduction to Programming in C

Course Link: Click Here

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These are Introduction to Programming in C Assignment 8 Answers


Question 1

Deletion from Doubly linked list
In this question, you have to write code to remove the first node in a doubly linked list containing a specified number. The code to create the linked list is already given.
The main() function calls a function removeData(head,tail,n) to remove the first node containing data n from the linked list. Complete the code by writing the missing function. You can also write additional functions which you may need.

Input Format
You will be given a positive number N in the first line.
This will be followed by a line containing N integers.
This will be followed by an integer M.
Output format
The output will be the list after deleting M.

Solution:

#include <stdio.h>

#include <stdlib.h>

struct DoublyLinkedList {
  int data;
  struct DoublyLinkedList * prev;
  struct DoublyLinkedList * next;
};
/*
--------------------------
Create a new node
--------------------------
*/
struct DoublyLinkedList * createNode(int n) {
  struct DoublyLinkedList * newNodeptr;
  newNodeptr = (struct DoublyLinkedList * )
  malloc(sizeof(struct DoublyLinkedList));
  newNodeptr -> data = n;
  newNodeptr -> prev = NULL;
  newNodeptr -> next = NULL;
  return newNodeptr;
}

/*
--------------------------------
add a node at the end of a doubly linked list.
Tailptr is the address of the pointer to the end of the current list.
After adding the node, tail points to the new node inserted.
--------------------------------
*/

void appendNode(struct DoublyLinkedList ** tailptr, int n) {
  struct DoublyLinkedList * newNode;
  newNode = createNode(n);
  newNode -> prev = * tailptr;
  ( * tailptr) -> next = newNode;
  * tailptr = newNode;
}

void initializeList(
  struct DoublyLinkedList ** headptr,
  struct DoublyLinkedList ** tailptr,
  int n) {
  struct DoublyLinkedList * newNode;
  newNode = createNode(n);
  * headptr = newNode;
  * tailptr = newNode;
  return;
}

void printList(
  struct DoublyLinkedList * head,
  struct DoublyLinkedList * tail) {
  struct DoublyLinkedList * curr = head;
  while (curr != NULL) {
    if (curr -> next != NULL)
      printf("%d,", curr -> data);
    else printf("%d", curr -> data);

    curr = curr -> next;
  }
  return;
}

/*
---------------------------------------
remove the node that contains data as n
---------------------------------------
*/

void removeData(
  struct DoublyLinkedList ** headptr,
  struct DoublyLinkedList ** tailptr,
  int n) {
  
  struct DoublyLinkedList *curr = *headptr;

  while (curr != NULL) {
    if (curr->data == n) {
      if (curr->prev == NULL) {
        // If the node to be removed is the head
        *headptr = curr->next;
        if (*headptr != NULL) {
          (*headptr)->prev = NULL;
        }
        free(curr);
        return;
      } else {
        // If the node to be removed is not the head
        curr->prev->next = curr->next;
        if (curr->next != NULL) {
          curr->next->prev = curr->prev;
        }
        free(curr);
        return;
      }
    }
    curr = curr->next;
  }
}


int main() {
  int n;
  int i = 0;
  int m;
  struct DoublyLinkedList * head, * tail;
  scanf("%d", & n);
  if (n <= 0) {
    return 0;
  }
  scanf("%d", & m);
  initializeList( & head, & tail, m);

  for (i = 1; i < n; i++) {
    /* read the remaining elements */
    scanf("%d", & m);
    appendNode( & tail, m);
  }

  scanf("%d", & n);
  removeData( & head, & tail, n);
  printList(head, tail);
  return 0;
}

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These are Introduction to Programming in C Assignment 8 Answers


Question 2

Priority Queue using Linked List
In this question, a linked list is partially implemented where each element in the linked list is a structure of the following format:
struct node{
int id;
int priority;
struct node *next;
};

Solution:

#include <stdio.h>
#include <stdlib.h>

struct node {
  int id;
  int priority;
  struct node *next;
};

struct node *create_node(int id, int val) {
  struct node *newNode = (struct node *)malloc(sizeof(struct node));
  newNode->id = id;
  newNode->priority = val;
  newNode->next = NULL;
  return newNode;
}

struct node *append(struct node *list, struct node *e) {
  e->next = list;
  return e;
}

struct node *search(struct node *list, int id) {
  struct node *curr = list;
  while (curr != NULL) {
    if (curr->id == id) {
      return curr;
    }
    curr = curr->next;
  }
  return NULL;
}

void change_priority(struct node *list, int id, int val) {
  struct node *e = search(list, id);
  if (e != NULL) {
    e->priority = val;
  }
}

struct node *delete_node(struct node *list, struct node *e) {
  if (e == NULL) {
    return list;
  }

  if (e == list) {
    struct node *newHead = e->next;
    free(e);
    return newHead;
  }

  struct node *curr = list;
  while (curr->next != NULL) {
    if (curr->next == e) {
      curr->next = e->next;
      break;
    }
    curr = curr->next;
  }

  free(e);
  return list;
}

struct node *extract_max(struct node *list) {
  struct node *maxNode = NULL;
  struct node *curr = list;

  while (curr != NULL) {
    if (maxNode == NULL || curr->priority > maxNode->priority) {
      maxNode = curr;
    }
    curr = curr->next;
  }

  if (maxNode != NULL) {
    printf("Max: %d\n", maxNode->id);
  } else {
    printf("Max: -1\n");
  }

  return delete_node(list, maxNode);
}

int find_priority(struct node *list, int id)
{
  struct node *e = search(list, id);
  if (e != NULL)
    return e->priority;
  return -1;
}

int main() {
  char op;
  int id, val;
  struct node *list = NULL;

  int flag = 1;
  do {
    scanf("%c ", &op);
    switch (op) {
    case 'A':
      scanf("%d %d", &id, &val);
      list = append(list, create_node(id, val));
      break;
    case 'S':
      scanf("%d", &id);
      printf("%d %d\n", id, find_priority(list, id));
      break;
    case 'C':
      scanf("%d %d", &id, &val);
      change_priority(list, id, val);
      break;
    case 'M':
      list = extract_max(list);
      break;
    case 'E':
      flag = 0;
      break;
    }
  } while (flag == 1);
  return 0;
}

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These are Introduction to Programming in C Assignment 8 Answers

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These are Introduction to Programming in C Assignment 8 Answers


Course Name: Introduction to programming in C

Course Link: Click Here

These are Introduction to Programming in C Assignment 8 Answers


Question 1

In this question, you have to write code to remove the first node in a doubly linked list containing a specified number. The code to create the linked list is already given.
The main() function calls a function removeData(head,tail,n) to remove the first node containing data n from the linked list.
Complete the code by writing the missing function. You can also write additional functions which you may need.

These are Introduction to Programming in C Assignment 8 Answers

Input Format
You will be given a positive number N in the first line.
This will be followed by a line containing N integers.
This will be followed by an integer M.

These are Introduction to Programming in C Assignment 8 Answers

Output format
The output will be the list after deleting M.
Note : Only delete the first occurrence of M in list. If M is not present in the list, no change should happen to the list. Maintain the remaining elements in the original order.
Note : You do not have to add any additional code to print the list – once you code the removeData() function, the code will print the contents of the remaining list.

These are Introduction to Programming in C Assignment 8 Answers

Solution

#include <stdio.h>
#include <stdlib.h>

struct DoublyLinkedList {
  int data;
  struct DoublyLinkedList *prev, *next;
};

void initializeList(struct DoublyLinkedList **head, struct DoublyLinkedList **tail, int data) {
  *head = (struct DoublyLinkedList*) malloc(sizeof(struct DoublyLinkedList));
  (*head)->data = data;
  (*head)->prev = NULL;
  (*head)->next = NULL;
  *tail = *head;
}

void appendNode(struct DoublyLinkedList **tail, int data) {
  struct DoublyLinkedList *newNode = (struct DoublyLinkedList*) malloc(sizeof(struct DoublyLinkedList));
  newNode->data = data;
  newNode->prev = *tail;
  newNode->next = NULL;
  (*tail)->next = newNode;
  *tail = newNode;
}

void printList(struct DoublyLinkedList *head, struct DoublyLinkedList *tail) {
  while (head != NULL) {
    printf("%d", head->data);
    if (head != tail) {
      printf(",");
    }
    head = head->next;
  }
}

void removeData(struct DoublyLinkedList **headptr, struct DoublyLinkedList **tailptr, int n) {
  struct DoublyLinkedList *current = *headptr;

  // Find the node to be removed
  while (current != NULL && current->data != n) {
    current = current->next;
  }

  // If the node is not found, do nothing
  if (current == NULL) {
    return;
  }

  // If the node is the head
  if (current == *headptr) {
    *headptr = current->next;
    if (*headptr != NULL) {
      (*headptr)->prev = NULL;
    }
  }
  // If the node is the tail
  else if (current == *tailptr) {
    *tailptr = current->prev;
    (*tailptr)->next = NULL;
  }
  // If the node is in the middle
  else {
    current->prev->next = current->next;
    current->next->prev = current->prev;
  }

  free(current);
}

int main() {
  int n;
  int i = 0;
  int m;
  struct DoublyLinkedList *head, *tail;
  scanf("%d", &n);
  if (n <= 0) {
    return 0;
  }
  scanf("%d", &m);
  initializeList(&head, &tail, m);
  for (i = 1; i < n; i++) {
    /* read the remaining elements */
    scanf("%d", &m);
    appendNode(&tail, m);
  }

  scanf("%d", &n);
  removeData(&head, &tail, n);
  printList(head, tail);
  return 0;
}
//These are Introduction to Programming in C Assignment 8 Answers

These are Introduction to Programming in C Assignment 8 Answers


Question 2

You are given a non-negative number less than 10000000 (1 followed by 7 zeroes). You have to divide the number into the following components, and print them in the following order.
1. The part of the number which is less than a thousand.
2. The part of the number which is between a thousand and a lakh (10^5)
3. The part of the number which is between a lakh and a crore (10^7)

These are Introduction to Programming in C Assignment 8 Answers

You should terminate printing when no higher power of 10 is present to be printed.
Sample input
134847
Sample Output
847
34
1

These are Introduction to Programming in C Assignment 8 Answers

Solution

#include <stdio.h>

int main() {
    int num;
    scanf("%d", &num);
    int crore = num / 10000000;
    num %= 10000000;
    int lakh = num / 100000;
    num %= 100000;
    int thousand = num / 1000;
    num %= 1000;
    int lessThanThousand = num;

    if (crore > 0) {
        printf("%d\n", lessThanThousand);
       printf("%d\n", thousand);
      printf("%d\n", lakh);
       printf("%d", crore);
    } else if (lakh > 0) {
       printf("%d\n", lessThanThousand);
       printf("%d\n", thousand);
      printf("%d", lakh);
    } else if (thousand > 0) {
       printf("%d\n", lessThanThousand);
       printf("%d", thousand);
    } else {
        printf("%d", lessThanThousand);
    }

    return 0;
}
//These are Introduction to Programming in C Assignment 8 Answers

These are Introduction to Programming in C Assignment 8 Answers

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These are Introduction to Programming in C Assignment 8 Answers


These are Introduction to programming in C Assignment 8 Answers
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